2. Prove: 1- tan²theta/cot²theta-1= tan²theta
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Step-by-step explanation:
let theta = x
so,
LHS,,
(1-tan²x)/(cot²x-1)
= (1-tan²x)/(1/tan²x-1)
= [1-tan²x]/[(1-tan²x)/tan²x]
= 1×tan²x
= tan²x
so, => tan²theta = RHS
hence proved....
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