Question

2. Prove divisibility by 9. a. Write 5 digits whose sum is divisible by 9. ____ + ____ + ____ + ____ + ____ = ________.

Use the five digits in any order to form a 5-digit number. ______________ Divide the number by 9. Is it divisible? _____________

b. Write 6 digits whose sum is divisible by 9. ____ +____ + ____ + ____ + ____ + ____ = ________. Use the six digits in any order to form a 6-digit number. ______________ Divide the number by 9. Is it divisible? _____________



c. Use the divisibility rule to form a 7-digit number divisible by 9.​

Answer 1

Answer:

It's too easy you must try

Answer 2

Answer:

5 digit number : 12348

6 digit number = 126945

7 digit number = 1234890

Step-by-step explanation:

a. divisiblity  of 9 is the sum of all the digits in number is divisible by 9

so, let the number be 1,2,3,,4,8

1+2+3+4+8 = 18 ,

which is a multiple of 9

let the order be 23148

then also it will be divisible by 9 , because just the order of digits changed not the number

b. 6 digits whose is divisible by 9 =

1,2,6,9,4,5

1+2+6+9+4+5 = 27  it is divisible by 9

let change the sequence , 542169

then also the number is divisible by 9

c. the 7 digits be , 1234890

the sum of these number is equal to 27

which is divisble by 9

and by seeing above two cases that by just interchanging the digit let it be ( 9084321) the sum does not change.