Question

2. Prove that equal chords of congruent circles
subtend equal angles at their centre.​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

*Answer:

In △AOB and △PXQ

AO=PX

[Radius of congruent circles are equal]

∠AOB=∠PXQ [Given]

BO=QX [Radius of congruent circles are equal]

△AOB≅△PXQ [SAS congruence rule]

∴AB=PQ [CPCT]

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