Question

2.
Prove that the angle opposite to the equal sides of an equilateral
triangle are equal.​

Answer 1

Answer:

In triangel ABD and ACD

angle A =angleA(AD is bisector of angleA)

AD=AD(common)

angle D=angleD(AD perpendicular BC)

By ASA condtion ABD congruent to ACD

By CPCT angle B=angleC

Hence proved!

Step-by-step explanation: