2.
Prove that the angle opposite to the equal sides of an equilateral
triangle are equal.
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Answer:
In triangel ABD and ACD
angle A =angleA(AD is bisector of angleA)
AD=AD(common)
angle D=angleD(AD perpendicular BC)
By ASA condtion ABD congruent to ACD
By CPCT angle B=angleC
Hence proved!
Step-by-step explanation:
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