2. Prove that the perpendicular drawn from the centre to chord bisects the chord.
3. In the given figure, C and D are points on the semicircle and AB is the diameter.
ZBAD = 70° and 2DBC = 35°. Calculate ZABD and 2BDC.
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Given :
A chord PQ of a circle C(O,r) and perpendicular OL to the chord PQ.
To Prove :
LP=LQ
Construction :
Join OP and OQ.
Proof :
In triangles PLO and QLO,
OP=OQ=r
OL=OL
∠OLP=∠OLQ
So, by RHS-criterion of congruence,
△PLO≅△QLO
PL=LQ
Hence, proved.
Thus, the given statement is true.
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