Question

2. Prove that the sum of first n even numbers
=n(n+1).​

Answer 1

Answer:

Sum of first n terms of an A.P.(Arithmetic Progression)

= (n/2) * [2*a + (n-1)*d].....(i)

where, a is the first term of the series and d is

the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.(i), we get

Sum = (n/2) * [2*2 + (n-1)*2]

= (n/2) * [4 + 2*n - 2]

= (n/2) * (2*n + 2)

= n * (n + 1)

Step-by-step explanation:

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