Question

2
Q2. In the figure, O is the centre of the circle. Find the value of x.
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Answer 1

Answer:

We have AOC = 135˚

then COB = 180˚ - 135˚ = 45˚

but x = COB/2 = 45˚/2 = 22.1/2˚

(ii) In BOC,

OB = OC

So OCB = OBC = 40˚

In BOC,

BOC = 180 – (40 + 40)˚

= 180˚ – 80˚

So x = BOC/2

= 100˚/2 = 50˚

(iii)

APC = ½ AOC

= ½ × 120˚ = 60˚

Since, ABCD is a cyclic quadrilateral

CBD = x is the exterior angle

So x = APC = 60˚

hope it will help you dear ❣️❤️❣️