Question

[2]
Question 4
A stone tied to an end of a string 40 cm long is whirled in a circle at a constant
speed. If the stone makes 28 revolutions in 20 seconds, calculate the magnitude of
its linear velocity​

Answer 1

Answer:

Radius = r = 50 cm = 0.5 m

» In 20 sec revolution = 10

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» in 1 sec revolution = 10/20 = 1/2 Hz

» N = 1/2 Hz

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Now

» Angular Velocity = w = 2πn

» Angular Velocity = w = 2×3.14×0.5

» Angular Velocity = w = 3.14

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» Radial Acceleration = w²r

» Radial Acceleration = (3.14)²×0.5 m/s²

» Radial Acceleration = 4.93 m/s²

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