2 questions please let me know
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given that 2 is root of the equation
on putting x=2 in the equation
we get,
k(2)^2-14×2+8=0
4k-28+8=0
4k-20=0
4k=20
k=20/4
k=5
hope it helps!!
on putting x=2 in the equation
we get,
k(2)^2-14×2+8=0
4k-28+8=0
4k-20=0
4k=20
k=20/4
k=5
hope it helps!!
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