2^r-5=5 find it r and how do you find it
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Hii its tom85
2^r - 5 = 5
2^r = 10
using log on both side
rlog2 = log10
r = ( log5 + log2)/log2
r=log5/log2 +1
concept
log(a*b)=log a + log b
__________/\_________☺️
hope it helps you dude
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