Question

2. Radius of a circle with centre O is 25 cm.
Find the distance of a chord from the centre if
length of the chord is 48 cm.​

Answer 1

Answer:

R = 25 cm

length of cord QP=48 cm

now bisect the cord perpendicularly from centre O to point S on QP

now, by phythagoras theorem

in triangle OSP

OP^2=OS^2+PS^2

( as OP is radius therefore OP=25 cm

PS = 24cm as OS bisect QP)

(25)^2=OS^2+(24)^2

625=OS^2+576

625-576=OS^2

49=OS^2

OS=7

THEREFORE DISTANCE BETWEEN THE CENTRE OF THE CIRCLE AND THE CORD IS 7cm