Question

2) Raj is painting the walls and ceiling
of a cuboidal hall with length, breadth
and height of 15m, 10m and 7m
respectively. From each can of paint
50m.sg. of area is painted. How many
cans of paint will she need to paint the
room?​

Answer 1

Answer:

10 cans

Step-by-step explanation:

In the cuboid room, the paintable area (without the floor) is

= (lb + bh + bh + lh + lh)

= 2(lh + bh) + lb

= 2 [ (15×7) + (10×7) ] + (15×10)

= 2 (105+70) + 150

= 500 m²

1 can of paint = for 50 m² area

500 m² area = ? cans

= 500/50

= 10 cans

Answer 2

Step-by-step explanation:

the answer is 21 cans if raj is painting the walls