Math, asked by shaimakalim, 4 months ago

2. Reduce the matrix A to its normal form, where,
TO 1 -3 -
-11
1 0 1 1
А A
3 1 0 2

1 1 - 2 0

ON-​

Answers

Answered by scopeastronomical
0

Answer:

Let V be a vector space over a field K. Then a basis with respect to which the matrix has the required form exists if and only if all eigenvalues of the matrix lie in K, or equivalently if the characteristic polynomial of The diagonal entries of the normal form are the eigenvalues (of the operator), and the number of times each eigenvalue occurs is called the algebraic multiplicity of the eigenvalue.

Step-by-step explanation:

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