2 resistance of 10 ohms and 20 ohms are connected in parallel across a supply voltage of 110 volts find effective resistance
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effective resistance will be 6.6 ohm
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The formula i use is called, Product over Sum. Which means it is figured by their multiplied resistances divided by their sum. It is applied by pairs of known resistances. Starting with 20 and 30 Ohms, 600 is divided by 50. Using a quick mental calculation, the first pair has a resistance of 12 Ohms. Then, do that with 12 Ohms and 10 Ohms. 120 Ohms divided by 22. The answer is, about 5.5 Ohms. By this interesting development, we are reminded that resistances in parallel are effectively never more than the least one.
The students decide to assemble a convenient experiment and will run one amp through them all in parallel and measure their voltage. Watching the Amperage gauge on their teacher’s power supply. As one begins to turn it up to an Amp, another is watching its voltage till an Amp is perfectly applied. But as they carefully do that, watching the Amp gauge, another screams, their 10 Ohm resistor turns black and smokes as they were only pumping out 2 or 3 tenths of an Amp. What happened? What did they need, to make this simple experiment not so embarass-king?
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