Question

2 resistor are connected in series given as equivalent resistance of 10 ohms when connected in parallel gives 2.4 ohms then the individual resistance are_________
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Answer 1

Answer:The individual resistance are 6 ohms and 4 ohms.

Explanation:

Given that, two resistors are connected in series gives an equivalent resistance of 10Ω.

When connected in parallel, gives 2.4Ω. We need to find the individual resistance.

Equivalent resistance in series combination is :

R=R1+R2

10=R1+R2--------------(1)

Equivalent resistance when connected in parallel is :

1/R=1/R1+1/R2

2.4=1/R1+1/R2-------------(2)

On solving (1) and (2) we get :

R1=6 Ω

R2= 4 Ω

So, the individual resistance are 6 ohms and 4 ohms. Hence, this is the required solution.

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Answer 2

Answer:

R1 = 6 ohm

R2= 4 ohm

Explanation:

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