2 resistors of resistances 200k ohm and 1M ohm respectively form a potential barier with outer junctions maintained at potentials of +3v and -15v . Then the potential @the junction betweeen the resistors is
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Explanation:
The resistors are in series connection.
Given that R1 is 125 ohm greater than R2.
Thus R1=R2+125
Total resistance =1375ohm
R1+R2=1375
R2+125+R2=1375
2R2=1375−125=1250
R2=1250/2=625ohm
R1=R2+125=325+125=750 ohm
R1=625 ohm and R2=750 ohm
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