Math, asked by vishal75935, 9 months ago

2. Right angled triangle, ABC has hypotenuse of length 4√10 cm and the other side is 6 cm.
If the smallest angle is at B, find cot B​

Answers

Answered by amitnrw
11

CotB  =  √31/3

Step-by-step explanation:

ABC has hypotenuse of length 4√10 cm

the other side is 6 cm.

Third side  = √(4√10)² - 6²

=> Third side  = √160 - 36

=> Third side  = √124

=> Third side  = 2√31

smallest angle is at B

=> Side opposite to ∠B  = 6

and side AB & BC  are  4√10   & 2√31

CotB  =  2√31/6

=> CotB  =  √31/3

Learn more:

In triangle pqr right angled q. Pr = 13cm and pq - qr = 7cm ...

https://brainly.in/question/11116652

If cot theeta = 8/15 then find the value of cosec theeta and sec theeta ...

https://brainly.in/question/13172765

In the diagram, given below,triangle ABC is right-angled at B and BD ...

https://brainly.in/question/2737587

Answered by selinmary23
6

Answer:

Hope it helps

I am Sunjana Ryisfa.C.R

If you know me just comment

If it helps you put thanks

Bye

Attachments:
Similar questions