Math, asked by platinu, 3 months ago

2) Riya and Jiya are very health conscious and go for running every morning. Riya runs along the boundary of a square shaped park of side 20m and Jiya runs along a triangular shaped park having sides 28m, 25m and 35m. Both takes four rounds around the park.

Who runs longer distance by how much ?

Answers

Answered by rimeld464
6

Step-by-step explanation:

Please note that the values of charge and mass of the residual particles are of protons when hydrogen gas is enclosed in the discharge tube. In case some other gas is enclosed, then the positive residues differ in the values of mass and charge. This means that unlike electron, a proton is not a universal particle.

Answered by RvChaudharY50
0

Question :- Riya and Jiya are very health conscious and go for running every morning . Riya runs along the boundary of a square shaped park of side 20m and Jiya runs along a triangular shaped park having sides 28m, 25m and 35m. Both takes four rounds around the park.

(i) Who runs longer distance by how much ?

a) Riya by 32 m

b) Jiya by 32 m

c) Riya by 8 m

d) Jiya by 8 m

(ii) If both takes 5 minutes to complete one round of field, whose speed is less?

a) Riya

b) Jiya

c) Both have same speed

(iii) If Jiya runs around a rectangular park of side 25m and 30 m then how much

distance she cover in 1'2 round

a) 110 m

b) 220m

C) 165 m

d) 55m

Solution :-

→ Side of square = 20 m .

→ Perimeter of square = 4 * side = 4 * 20 = 80 m .

so,

→ Distance covered by Riya in 4 rounds = 4 * perimeter = 4 * 80 = 320 m.

and,

→ sides of ∆ park = 28m, 25m and 35m.

→ perimeter = 28 + 25 + 35 = 88 m .

so,

→ Distance covered by Jiya in 4 rounds = 4 * perimeter = 4 * 88 = 352 m.

therefore,

→ Jiya covered more distance by = 352 - 320 = 32 m. (Ans.b)

now,

→ Distance covered by Riya = 320 m.

→ Time taken = 5 minutes .

so,

→ speed of Riya = Distance / speed = 320/5 = 64m/min.

and,

→ Distance covered by Jiya = 352 m.

→ Time taken = 5 minutes .

so,

→ speed of Jiya = Distance / speed = 352/5 = 70.4m/min.

therefore, speed of Riya is Less.

now,

→ Perimeter of rectangle = 2(Length + Breadth) = 2(25 + 30) = 2 * 55 = 110m .

hence,

→ Distance covered by Jiya in 1'2 rounds = 110 * 1.5 = 165 m. (Ans.)

Similar questions