Question

2 root 12 - 3 root 32 + 2 root 48

Answer 1

$2 \sqrt{12 } - 3 \sqrt{32} + 2 \sqrt{48}$
=2√12+2√48-3√32
=2√12+2√12*√4 -3√32
=4√12*2-3√32 (√4=2)
=8√12 -3√32
=8√3*√4 -3√8*√4
=8√3*2 -3√8*2
=16√3 -6√8
=16√3 -6√2*√4
=16√3 -6√2*2
=16√3 -12√2
=4(4√3 -3√2)

Answer 2

Answer:

2

12

−3

32

+2

48

=2√12+2√48-3√32

=2√12+2√12*√4 -3√32

=4√12*2-3√32 (√4=2)

=8√12 -3√32

=8√3*√4 -3√8*√4

=8√3*2 -3√8*2

=16√3 -6√8

=16√3 -6√2*√4

=16√3 -6√2*2

=16√3 -12√2

=4(4√3 -3√2)

Step-by-step explanation:

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