Question

2\root 3 -1 please give me answer​

Answer 1

$\frac{2}{ \sqrt{3} - 1 } \\ \\ = \frac{2}{ \sqrt{3} - 1} \times \frac{ \sqrt{3} + 1 }{ \sqrt{3} + 1} \\ \\ = \frac{2 \sqrt{3} + 2}{( { \sqrt{3}) }^{2} - 1 } \\ \\ = \frac{2( \sqrt{3} + 1)}{3 - 1} \\ \\ = \frac{ \not2( \sqrt{3} + 1) }{ \not2} \\ \\ = \sqrt{3} + 1$