Question

2/root 3- root 2 rationalise the denominator ​

Answer 1

Answer:

$\huge\boxed{\fcolorbox{blue}{orange}{HELLO\:MATE}}$

=$\dfrac{2}{(\sqrt{3}-\sqrt{2})}$

=$\dfrac{2×(\sqrt{3}+\sqrt{2})}{(\sqrt{3}-\sqrt{2}×(\sqrt{3}+\sqrt{2})}$

$\large\green{\boxed{(a+b)(a-b)=a^{2}-b^{2}}}$

=$\dfrac{2×(\sqrt{3}+\sqrt{2})}{(\sqrt{3}^{2})-(\sqrt{2}^{2})}$

=$\dfrac{2×(\sqrt{3}+\sqrt{2})}{3-2}$

=$\dfrac{2\sqrt{3}+2\sqrt{2}}{1}$

=$2×(\sqrt{3}+\sqrt{2})$

$\large\orange{\boxed{ANSWER:2×(\sqrt{3}+\sqrt{2})}}$