Math, asked by madstuffwithdivakar1, 10 months ago

2 root 3 x^2 +5x-4 root 3

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Answered by vikasreddy1809
0

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Answered by Nikhil0204
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  \huge\green{\mathfrak{\underline{\underline{ANSWER}}}}

2 \sqrt{3}  {x}^{2}  + 5x - 4 \sqrt{3}  \\ 2 \sqrt{3 }  {x}^{2} +  8x - 3x - 4 \sqrt{3}  \\ 2x( \sqrt{3} x + 4) -  \sqrt{3} ( \sqrt{3} x + 4) \\ (2x -  \sqrt{3} )( \sqrt{3} x + 4)

 =  > x =  \frac{ \sqrt{3} }{2} or \frac{ - 4}{ \sqrt{3} }

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