Math, asked by swatikatekar, 6 months ago

2 root 5– root 2 upon 2 root 5+root 2 rationalise the denominator

Answers

Answered by sonia28066
0

Answer:

22-4√7/18

Step-by-step explanation:

(2√5-√2)/(2√5+√2)*(2√5-√2)/(2√5-√2)

((2√5)SQ.+√2SQ.-2*2√5*√2)/(2√5SQ-√2SQ)

(20+2-2*2√5)/20-2

22-4√7/18

HOPE ITS CORRECT..

Answered by lalitha14rlsv
1

Answer:

11-2√10 / 9

Step-by-step explanation:

Q :2√5 - √2 / 2√5 + √2

=> (2√5 - √2) / (2√5 + √2)   x (2√5 - √2) / (2√5 - √2)    

=> (2√5 - √2) (2√5 - √2)  /  (2√5 + √2) (2√5 - √2)

=> ( 2√5 - √2)²  /  (2√5)²  (√2)²                                  ------(a+b) (a-b)= a² -b²

=>  ( 2√5 )²  - 2 (2√5) (√2) + (√2)² /  20-2                    ------(a-b)² = a² - 2ab +b²

=>  20 - 4√10 +2 / 18                                                        ----- √a . √a=a

=>  22-4√10 / 18

=>  2(11-2√10) / 18

=>  11-2√10 / 9.

Hope it helps:)

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