2 root 5– root 2 upon 2 root 5+root 2 rationalise the denominator
Answers
Answered by
0
Answer:
22-4√7/18
Step-by-step explanation:
(2√5-√2)/(2√5+√2)*(2√5-√2)/(2√5-√2)
((2√5)SQ.+√2SQ.-2*2√5*√2)/(2√5SQ-√2SQ)
(20+2-2*2√5)/20-2
22-4√7/18
HOPE ITS CORRECT..
Answered by
1
Answer:
11-2√10 / 9
Step-by-step explanation:
Q :2√5 - √2 / 2√5 + √2
=> (2√5 - √2) / (2√5 + √2) x (2√5 - √2) / (2√5 - √2)
=> (2√5 - √2) (2√5 - √2) / (2√5 + √2) (2√5 - √2)
=> ( 2√5 - √2)² / (2√5)² (√2)² ------(a+b) (a-b)= a² -b²
=> ( 2√5 )² - 2 (2√5) (√2) + (√2)² / 20-2 ------(a-b)² = a² - 2ab +b²
=> 20 - 4√10 +2 / 18 ----- √a . √a=a
=> 22-4√10 / 18
=> 2(11-2√10) / 18
=> 11-2√10 / 9.
Hope it helps:)
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