2 root 6 upon root 2 + root 3 + root 5 equals
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Given:
2 root 6 upon root 2 + root 3 + root 5
To Find:
Its value
Solution:
First we will change the given question into equation
2 root 6 = 2√6
Root 3 = √3
Root 5 = √5
According to the question
((2√6)/√2 ) + √3 + √5
= ((2√3×2)/√2) + √3 + √5 (∵6 = 3×2)
=(2×√2×√3)/√2) + √3 + √5 (∵ √a×b = √a×√b)
=2√3 + √3 + √5
= 3√3+√5
Hence, the answer is (3√3+√5).
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