Question

(2 root 8- 3 root 2) have power 2​

Answer 1

(2√8 - 3√2)²

Using algebraic identity : (x - y)² = x² - 2xy + y²

Here, x = 2√8, y = 3√2

By substituting the values :

(2√8 - 3√2)² = (2√8)² - 2(2√8)(3√8) + (3√2)²

= 4(8) - 12√(8 * 8) + 9(2)

= 32 - 12√64 + 18

= 50 - 12√64