Question

2/root3-1 plez help me to solve it​

Answer 1

Answer:

2/root 3+1=2*root 3-1/root 3+1*root 3-1

                =2*root 3-1/3-1

                =2*root 3-1/2

                =root 3-1

hope it helps

Answer 2

Answer:

√3 +1

Step-by-step explanation:

I hope you are familiar with concept of rationalization:

therefore,

$\frac{2}{\sqrt{3} -1} * \frac{\sqrt{3} +1 }{\sqrt{3} +1}$    ... multiplying and dividing by the conjugate of denominator

hence,

$\frac{2(\sqrt{3 }+1) }{(\sqrt{3})^2 - (1)^2 }$   ... by the identity, $a^2 - b^2 = (a+b)(a-b)$

= $\frac{2(\sqrt{3 }+1) }{(3-1)} = \frac{2(\sqrt{3}+1) }{2} = \sqrt{3} +1$