Question

2/root3-1 rationalise the following ​

Answer 1

Answer:

root 3 - 1

Step-by-step explanation:

$given \: \frac{2}{ \sqrt{3 - 1} } \\ for \: rationalising \: we \: havei \: to \: multiply \: \sqrt{3 - 1}in \: both \: the \: numerator \: and \: denominator \\ \\ \frac{2}{ \sqrt{3 - 1} } \times \frac{ \sqrt{3 - 1} }{ \sqrt{3 - 1} } \\ = \frac{2 \sqrt{3 - 1} }{ \sqrt{ {(3 - 1)}^{2} } } \\ = \frac{2 \sqrt{3 - 1} }{3 - 1} \\ = \frac{2 \sqrt{3 - 1} }{2} \\ = \sqrt{3 - 1}$

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