2-root3/2+root3 rationalize
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Answer:
(7-4√3)
Identity Used-
(a-b)²=(a²+b²+2ab)
(a+b)(a-b)=(a²-b²)
Explanation-
(i) We Have;
(2-√3)/(2+√3)
Multiply By (2-√3) in whole fraction!
(ii) (2-√3)/(2+√3)×(2-√3)/(2-√3)
(2-√3)(2-√3)/(2+√3)(2-√3)
[(2)²+(√3)²-(2)(2)(√3)]/[(2)²-(√3)²]
(7-4√3)/(4-3) = (7-4√3)
Hope It Helps!
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