Question

2-root5 upon 2+root 5

Answer 1

Step-by-step explanation:

$\frac{2-\sqrt{5} }{2+\sqrt{5} } =\frac{2-\sqrt{5} }{2+\sqrt{5} } *\frac{2-\sqrt{5} }{2-\sqrt{5} }$

$\frac{4-2\sqrt{5}-2\sqrt{5} +5 }{(2)^{2}-(\sqrt{5})^{2} }$

$\frac{4+5-2\sqrt{5}-2\sqrt{5} }{4-5}$

$\frac{9-4\sqrt{5} }{-1}$

$-(9-4\sqrt{5})=-9+4\sqrt{5}$

Hope this helps you

Answer 2

The answer is in photograph