2 s square - (1+2root2)s +root2
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0
Answer:
2s^2-(1+2√2)s+√2
=2s^2-s-2√2s+√2
=s(2s-1)-√2(2s-1)
=(s-√2)(2s-1)
Step-by-step explanation:
Answered by
0
Answer:
(2s-1) (s-√2)
Step-by-step explanation:
2s² - (1+2√2) s +√2
2s² -s -2√2s -√2
(pair 2s²-s and common s (2s -1)
and so..)
s(2s -1) -√2(2s -1)
(2s -1) (s - √2)
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