2.
Sahana drew a quadrilateral ABCD of which AB = 4cm, BC =5cm, CD=4.8cm, DA=
4.2cm and diagonal AC =6cm. I draw a triangle with equal area of that quadrilateral.
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Answered by
12
Step-by-step explanation:at first draw the quadrilateral like the picture .Then take the range of AC- and and keep the compass on D and cut the line .then take the range of AD and keep the compass on Christmas and cut .point out the cross point .
Hope it will help you
Attachments:
![](https://hi-static.z-dn.net/files/de5/d60e5f39f1ea6573bcb57518318a91b1.jpg)
![](https://hi-static.z-dn.net/files/d8d/6a381bc19976ed2ec08f0e40df3e5717.jpg)
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