Question

2.
Sahana drew a quadrilateral ABCD of which AB = 4cm, BC =5cm, CD=4.8cm, DA=
4.2cm and diagonal AC =6cm. I draw a triangle with equal area of that quadrilateral.​

Answer 1

Step-by-step explanation:at first draw the quadrilateral like the picture .Then take the range of AC- and and keep the compass on D and cut the line .then take the range of AD and keep the compass on Christmas and cut .point out the cross point .

Hope it will help you