Question

2 sandwiches and 3 croissants costs £11.
3 sandwiches and 6 croissants costs £19.50.
Find the cost of a sandwich.
Find the cost of a croissant.

Answer 1

if Question:-

2 sandwiches and 3 croissants costs £11

& 3 sandwiches and 6 croissants costs £19.50. Find the cost of a sandwich.

Find the cost of a croissant.

solution:-

Given:- a) 2 sandwiches and 3 croissants costs £ 11

b) 3 sandwiches and 6 croissants costs

£ 19.50

let, sandwiches be x and

croissants be y

so,now {by question}

=> 2x + 3y = 11 ....... ( 1 )

=> 3x + 6y = 19.50 ...... ( 2 )

To find cost an sandwiches

Multiply eq. ( 1 ) by 2

=> 4x + 6y =22 ..... ( 3 )

Now,

Substract eq. ( 2 ) from eq. ( 3 )

4x + 6y = 22

- ( 3x + 6y = 19.50 )

______________

x = 2.5 or (we can write it as £ 2.5 )

So Now,

put value of y in eq. ( 1 )

=> 2x + 3y = 11

=> 2(2.5) + 3y = 11

=> 5 + 3y = 11

=> 3y = 11 - 5

=> 3y = 6

=> x = 6/3

=> x = 2 or(we can write it as £2 )

Hence cost of one sandwiches and one croissants are £2.5 and £2 respectively.

OR

if Question:-

2 sandwiches and 3 croissants costs £11.3 & sandwiches and 6 croissants costs £19.50. Find the cost of a sandwich.

Find the cost of a croissant.

solution:-

Given:- a) 2 sandwiches and 3 croissants costs £ 11.3

b) sandwiches and 6 croissants costs

£ 19.50

let, sandwiches be x and

croissants be y

so,now {by question}

=> 2x + 3y = 11.3 ....... ( 1 )

=> x + 6y = 19.50 ...... ( 2 )

To find cost an sandwiches

Multiply eq. ( 1 ) by 2

=> 4x + 6y =22.6 ..... ( 3 )

Now,

Substract eq. ( 2 ) from eq. ( 3 )

4x + 6y = 22.6

- ( x + 6y = 19.50 )

______________

3x = 3.1

x = 3.1/3

x = 1.033 or (we can write it as

£1.033 )

So Now,

put value of y in eq. ( 1 )

=> 2x + 3y = 11

=> 2(1.033) + 3y = 11

=> 2.066 + 3y = 11

=> 3y = 11 - 2.066

=> 3y = 8.934

=> x = 8.934/3

=> x = 2.978 or(we can write it as £2.978 )

Hence cost of one sandwiches and one croissants are £3.1 and £2.978 respectively.

i hope it helps you.

Answer 2

answer

sandwich:£2.50

croissants:£2