2 satellites S1 and S2 around a planet in coplanar circular orbits in the same sense the periods of the revolution are 1 hour and 8 hour respectively the radius of orbit of S1 is equals to 10^4 km and s2 is closest to S1. 1. The speed of S2 relative to S1 ? 2. The angular speed of S2 as observed by astronaut in S1
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Hello dear, let's solve this,
Angular speed of satelite s2 w.r.t. s1 when they are closest to each other is given by,
w = |v1-v2| / |r1-r2|
But for planetary motion,
v1 = 2πr1/T1
v2 = 2πr2/T2
w = 2π× |(r1/T1 - r2/T2 ) ÷ (r1-r2)|
w = 2π× |(r1T2 - r2T1)/T1T2| ÷ |r1-r2|
w = 2π× | [r1T2- r2T1] / [T1T2/(r1-r2)] |
This is formula for angular speed of satelite s2 w.r.t. s1.
Hope this was useful...
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Answer:
The angular speed is 3*10^-4 rad/sec.
The angular speed is 3*10^-4 rad/sec.
The angular speed is 3*10^-4 rad/sec.
The angular speed is 3*10^-4 rad/sec.
The angular speed is 3*10^-4 rad/sec.
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