2 satellites X and Y revolve in the same circular orbit around the earth the mass of X is greater than the mass of y which of the following is Greater for X and Y speed only speed and gravitation force only potential energy and gravitational force kinetic energy and gravitational force
Answers
Answer:
Climbing stairs and lifting objects is work in both the scientific and everyday sense—it is work done against the gravitational force. When there is work, there is a transformation of energy. The work done against the gravitational force goes into an important form of stored energy that we will explore in this section.
Let us calculate the work done in lifting an object of mass m through a height h, such as in [link]. If the object is lifted straight up at constant speed, then the force needed to lift it is equal to its weight \text{mg}. The work done on the mass is then \text{W = Fd = mgh}. We define this to be the gravitational potential energy \left({\text{PE}}_{\text{g}}\right) put into (or gained by) the object-Earth system. This energy is associated with the state of separation between two objects that attract each other by the gravitational force. For convenience, we refer to this as the {\text{PE}}_{\text{g}} gained by the object, recognizing that this is energy stored in the gravitational field of Earth. Why do we use the word “system”? Potential energy is a property of a system rather than of a single object—due to its physical position. An object’s gravitational potential is due to its position relative to the surroundings within the Earth-object system. The force applied to the object is an external force, from outside the system. When it does positive work it increases the gravitational potential energy of the system. Because gravitational potential energy depends on relative position, we need a reference level at which to set the potential energy equal to 0. We usually choose this point to be Earth’s surface, but this point is arbitrary; what is important is the difference in gravitational potential energy, because this difference is what relates to the work done. The difference in gravitational potential energy of an object (in the Earth-object system) between two rungs of a ladder will be the same for the first two rungs as for the last two rungs.
Converting Between Potential Energy and Kinetic Energy
Gravitational potential energy may be converted to other forms of energy, such as kinetic energy. If we release the mass, gravitational force will do an amount of work equal to \text{mgh} on it, thereby increasing its kinetic energy by that same amount (by the work-energy theorem). We will find it more useful to consider just the conversion of {\text{PE}}_{\text{g}} to \text{KE} without explicitly considering the intermediate step of work. (See [link].) This shortcut makes it is easier to solve problems using energy (if possible) rather than explicitly using forces.
(a) The work done to lift the weight is stored in the mass-Earth system as gravitational potential energy. (b) As the weight moves downward, this gravitational potential energy is transferred to the cuckoo clock.
(a) The weight attached to the cuckoo clock is raised by a height h shown by a displacement vector d pointing upward. The weight is attached to a winding chain labeled with a force F vector pointing downward. Vector d is also shown in the same direction as force F. E in is equal to W and W is equal to m g h. (b) The weight attached to the cuckoo clock moves downward. E out is equal to m g h.
More precisely, we define the change in gravitational potential energy \text{Δ}{\text{PE}}_{\text{g}} to be
\text{Δ}{\text{PE}}_{\text{g}}=\text{mgh},
where, for simplicity, we denote the change in height by h rather than the usual \text{Δ}h. Note that h is positive when the final height is greater than the initial height, and vice versa. For example, if a 0.500-kg mass hung from a cuckoo clock is raised 1.00 m, then its change in gravitational potential energy is
\begin{array}{lll}\text{mgh}& =& \left(\text{0.500 kg}\right)\left({\text{9.80}\phantom{\rule{0.25em}{0ex}}\text{m/s}}^{2}\right)\left(\text{1.00 m}\right)\\ & =& \text{4.90 kg}\cdot {m}^{2}{\text{/s}}^{2}\text{= 4.90 J.}\end{array}
Note that the units of gravitational potential energy turn out to be joules, the same as for work and other forms of energy. As the clock runs, the mass is lowered. We can think of the mass as gradually giving up its 4.90 J of gravitational potential energy, without directly considering the force of gravity that does the work.
Explanation:
Speed of Y is greater than X
Gravitational force of X is greater than Y.
Potential energy of X is greater than Y.
Kinetic energy of Y is greater than X.
Explanation:
As, Y has less mass than the X. So, it's speed is greater.
Gravitational force depends upon gravity and mass. Gravity is same for both. But they have different mass. So, G.F of X is more than Y.
Potential energy also depends upon mass as they are at same distance. So, P.E of X is more than Y.
Kinetic energy of Y is greater than X. As, we know that k>E. depends upon mass but directly proportional to the square of velocity . So, it majorly depends upon velocity.