2) Satpal walks 2/3km from a place P , towards East and then from there 1⅚km towards
West.Where will he be now from P?
Answers
Answer:
The Current Position of Satpal is \frac{22}{21} \ km
21
22
km OR 1\frac{1}{21} \ km1
21
1
km from P towards west.
Step-by-step explanation:
Given:
Satpal Walks from P towards east = \frac{2}{3}\ km
3
2
km
Now from that point towards west = 1\frac{5}{7}\ km1
7
5
km
1\frac{5}{7}\ km1
7
5
km can be Rewritten as \frac{12}{7}\ km
7
12
km
Hence
Now from that point towards west = \frac{12}{7}\ km
7
12
km
We need to find the current Position from P.
SO to find the current Position we will Subtract from that point towards west with from P towards east.
framing in equation form we get;
current Position = \frac{12}{7}-\frac{2}{3}
7
12
−
3
2
Now taking LCM to make the Denominator common we get;
current Position = \frac{12\times3}{7\times3}-\frac{2\times7}{3\times7}= \frac{36}{21} -\frac{14}{21} = \frac{36-14}{21}= \frac{22}{21} \ km
7×3
12×3
−
3×7
2×7
=
21
36
−
21
14
=
21
36−14
=
21
22
km
\frac{22}{21} \ km
21
22
km can be written in Mixed fraction as 1\frac{1}{21} \ km1
21
1
km
So The Current Position of Satpal is \frac{22}{21} \ km
21
22
km OR 1\frac{1}{21} \ km1
21
1
km from P towards west.
Step-by-step explanation:
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