Question

2 sec ^2 theta - sec ^4 theta -2 cossec^2 theta = cot ^4 theta -tan ^4 theta

Answer 1

Answer:

hyy mate here instead of theta I have used the letter A

LHS:-

2sec^2A-sec^4A-2cosec^2A+cosec^4A=

2(sec^2A-cosec^2A)-(sec^4A-cosec^4A)=

2(sec^2A-cosec^2A)-(sec^2A-cosec^2A)(sec^2A+sec^2A)=

(sec^2A-cosec^2A)(2-sec^2A-cosec^2A)=

(1+tan^2A-1-cot^2A)(2-1-tan^2A-1-cot^2A)=

(tan^2A-cot^2A)-(tan^2A+cot^2A)=

-(tan^4A-cot^4A)=

-->cot^4A-tan^4A--ans..

Step-by-step explanation:

hope you understand and mark me as brainliest