2) Seven equal charges are placed at the corners of a cube of side x at a,b,c,d,e,f,g respectively. No charge is placed at h. EF at the centre of the cube is
A) 7kQ/x^2 towards h
B) 7 kQ/x^2 towards b
C) Zero
D) 2 KQ/ 3x^2 towards h
PLEASE ANSWER ASAP!
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Side of the cube =a
Length of each diagonal =
a
2
+a
2
+a
2
=
3
a
Distance of each corner from centre O= half the diagonal =
2
3
a
Potential at O due to charge at each corner =
4πε
o
1
3
2
a
q
=
4πε
o
1
3
a
2q
Therefore, net potential at O due to all the 8 charges at the corners of the cube,V=8×
4πε
o
1
3
a
2q
=
4πε
o
1
a
3
16q
The electric field at O due to charges at all the corners of cube is zero, since, the electric fields due to charges at opposite corners such as A and H, G and E, F and C are equal and opposite.
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