Question

2. Show that every positive odd integer is of the form 4q + 1 or 4q + 3, where q is
some integer​

Answer 1

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teach

Х

If r = 1

Our equation becomes

If r = 3

Our equation becomes

a = 4q + r

a = 4q+3

a = 4q+r

a = 4q + 1

This will always be an odd

integer

This will always be an odd

integer

Therefore, any odd integer is of the form 49 + 1 or 4q + 3

Hence proved.

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