2. Show that the points A(7,10), B(-2,5), C(3,-4) are the
vertices of a right angled triangle
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Use distance formula
AB^2 = (-9)^2 + (-5)^2 =81+25= 106
BC^2= 5^2+(-9)^2 =25+81 =106
CA^2=(-4)^2+(-14)^2= 16+196=212
Ie CA^2=AB^2+BC^2
Hence right triangle
AB^2 = (-9)^2 + (-5)^2 =81+25= 106
BC^2= 5^2+(-9)^2 =25+81 =106
CA^2=(-4)^2+(-14)^2= 16+196=212
Ie CA^2=AB^2+BC^2
Hence right triangle
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