Question

2 sides of a triangle are 8cm and 11cm and perimeter of a triangle is 32cm. Find the length of third size 0​

Answer 1

Answer:

Now, a+b+c=2s

8+11+c=32

c=13

Therefore,

s−a=16−8=8,s−b=16−11=5,s−c=16−13=3

Hence, area of given triangle =

s(s−a)(s−b)(s−c)

=

16×8×5×3

=8

30

cm

2