Question

2) Sides of square is 7, what is the ratio of the side to the hypotenuse of the square?​

Answer 1

Answer:

If the side of the square is 7, then the ratio of its side to the hypotenuse is 1 : √2

Step-by-step explanation:

Given

Length of the side of the square = 7

$side^{2} + side^{2} =hypotenuse^{2}$

$Hypotenuse^{2}=\sqrt{side^{2}+side^{2} }\\\\= \sqrt{7^{2} +7^{2} } \\\\= \sqrt{49+49} \\\\=\sqrt{98}$

So the ratio of the side to hypotenuse =$\frac{7}{\sqrt{98} } \\\\=\frac{7}{\sqrt{49} *\sqrt{2} } \\\\=\frac{7}{7*\sqrt{2} } \\\\=\frac{1}{\sqrt{2} }$

So, the ratio of the side of the square to the hypotenuse is 1 : √2

Answer 2

Answer:

The ratio of the side to the hypotenuse of the square = 1 : $\sqrt{2}$

Step-by-step explanation:

in square all sides has same value.

so ; let side of square s = 7

four sides of square has same value = 7.

from pythagoras theorem, $hypotenuse^{2}$ = $side^{2}$ +

$hypotenuse^{2}$ = $7^{2}$ +

$hypotenuse^{2}$ = 49 + 49 = 98

hypotenuse = $\sqrt{98}$ = 9.9

the ratio of the side to the hypotenuse of the square = 7 : $\sqrt{98}$

                                                                                        = 7: $\sqrt{49*2}$

                                                                                        = 7 : 7$\sqrt{2}$

the ratio of the side to the hypotenuse of the square = 1 : $\sqrt{2}$