Question

2 simple pendulum having length 0.17m and 0.49m are made to accelerate at a place where g = 10m/s^2.Find the ratio of their time period.​

Answer 1

Answer:

Explanation:

An oscillatory motion must be simple harmonic if: A.' the amplitude is small ... A particle is in simple harmonic motion with period T. At time t= 0 it is at the equilibrium ... Of the following times, at which time is it furthest from the equilibrium point? ... in equilibrium at the center of its path because the acceleration is zero there.

A pendulum with a string of length 2 m has a period of about 2.8 s. What would be the period of the pendulum if the length of the string were increased to 8 m? The correct answer is: C. The period of a pendulum is proportional to the square root of the length of the string.