2.sin-¹(3/5) = tan-¹(24/7)
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Let sin−153=x⇒sinx=53.
⇒cosx=1−(53)2=54
∴tanx=43
∴x=tan−143⇒sin−153=tan−143
Now, we have:
L.H.S.=2sin−153=2tan−143
=tan−1⎛1−(43)22×43
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