Question

√2 sin 135° cos210° tan240° cot300° sec330°​

Answer 1

Answer:

1

Step-by-step explanation:

I open all terms differently for good explanation, in exam you should do in one line by line form

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Answer 2

Question:-  Solve $\sqrt{2} sin 135* cos210* tan240* cot300* sec330$

Answer:-

$\sqrt{2} sin 135 * cos210* tan240 * cot300 * sec330 = 1$

Step-by-step explanation:

According to the question:-

$1. \sqrt{2} sin 135\\ = \sqrt{2} sin (180-45)\\= \sqrt{2} sin 45\\=\sqrt{2} * \frac{1}{\sqrt{2} } \\= 1$

$2. cos 210\\= cos(270-60)\\=-sin 60\\= - \frac{\sqrt{3} }{2}$

$3. tan 240\\= tan (270-30)\\= cot 30\\=\sqrt{3}$

$4. cot 300\\= cot (360-300)\\=cot 60\\= - \frac{1}{\sqrt{3} }$

$5. sec 330\\= sec(360-30)\\=sec30\\=\frac{2}{\sqrt{3} }$

Now,

$=\sqrt{2} sin 135* cos210* tan240* cot300* sec330\\=1*(-\frac{\sqrt{3} }{2}) * \sqrt{3} * (-\frac{1}{\sqrt{3} }) * \frac{2}{\sqrt{3} } \\=1$

Learn more:-

1. Trigonometry functions:-

https://brainly.in/question/42022714?msp_srt_exp=5

2. Trigonometry formulas and table:-

https://brainly.in/question/4068827?msp_srt_exp=5

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