Question

2 sin-1x का मान बताइए
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Answer 1

Step-by-step explanation:

squaring to both side 2sin@-1x =

4sin^2@-1x=0

4(cos^2@-1)-1x=0

4(cos^2@-1)=1x

cos^2@-1=1x/4

cos^2@=5/4

cos@=√5/√4

cos@=√5/2

(√5=2.24)

@=1.12