2 sin^2 30 cot 30-3cos^2 60 sec^2 30
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2sin^2 30 cot30-3cos^2 60 sec^2 30
= 2×(1/2)^2×√3-3×(1/2)^2×(2/√3)^2
= 2×1/4×√3-3×1/4×4/3
= √3/2-3/4×4/3
= √3/2.is the answer
= 2×(1/2)^2×√3-3×(1/2)^2×(2/√3)^2
= 2×1/4×√3-3×1/4×4/3
= √3/2-3/4×4/3
= √3/2.is the answer
raj1177:
answer is √3/2-2
Answer given by me is correct. If you don't believe pls solve this problem yourself.
Vese answer correct tha na.
ha
Thanx
in my text book my ans is cooerct
Answer check kar Lena vese mera answer 100% correct hai.
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