Question

2 sin^2 30 ×tan^ 2 32× tan^2 58÷3(sec^2 33 -cot ^2 57)+ cos^2 30÷sin^2 60

Answer 1

Answer:

Step-by-step explanation:

here is the answer

Answer 2

Answer:

Step-by-step explanation:

2sin²30.tan²32.tan²58/3(sec²33-cot²57) + cos ²30/sin²60

->2(1/2)².cot²(90-58).tan²58 ÷3(cosec²(90-57) - cot²57) +sin²(90-60)/sin²60

->2(1/4)×cot²58× tan²58÷ 3( cosec²57- cot²57) +sin²60/sin²60

-> (1/2)×(1/tan²58)×tan²58÷3(1) + 1

->1/2÷3 +1

->3/2+1

->3+2/2

->5/2

Hope it will help...