Question

2 sin ^2 A - cos ^2 A =2, find the value of A. Plzzzz answer this ​

Answer 1

Answer:

➡2sin²A-cos²A=2

➡2sin²A-1+sin²A=2

➡3sin²A=3

➡sin²A=1

➡sinA=1

➡A=90

Answer 2

Answer:

2sin²A-cos²A= 2

2sin²A-( 1-sin²A)=2

2sin²A- 1+sin²A=2

3sin²A-1=2

3sin²A= 3

sin²A= 1=sin²90°

A=90°

hope it helps ✨