Question

2 sin^2 x = 3 sin x - 1
Solve it for x​

Answer 1

hey mate...

here is your answer...

x = 7\pi / 6 or 11\pi / 6 or 3\pi /2

We may identify this as a quadratic equation in  sin  x  and factorise it as a trinomial to obtain the solutions as :

(2 sin x + 1 ) (sin x + 1 ) = 0

(2 sin x + 1) (sin x + 1) = 0

>> sin x = - 1 / 2 or sin x = -1

>> x = 7\pi / 6 or 11\pi / 6 or 3\pi /2

hope it helps...

Answer 2

Answer:

Check the attachment !!