Question

2 sin^2theta -costheta=1​

Answer 1

Answer:

I don't think there is any specific formula for sin^2 2x

Well you try some of these

We know cos2x=1–2sin^2(x)

So from here sin^x=(1-cos2x)/2

Likewise sin^2x= (1-cos4x)/2

Or

You can also change in all sine or all cosine

Like we know that sin2x=2sinxcosx

So sin^2(2x)=4sin^2(x)cos^2(x)

Now either change cosine into sine or change sine into cosine

It will be

Sin^2(2x)=4sin^2(x)-4sin^4(x)

Or sin^2(2x)=4cos^2(x)-4cos^4(x)

Hope it helps.

Step-by-step explanation:

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